The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per `m^2` is Rs 4.

Explanation

Given the side of the rhombus,` b = 6 cm`
Also, Given the altitude of rhombus, `h = 4 cm`, Area of the rhombus when base(side) and altitude`(h)`
are given is given by` A = base xx height`
Thus, Area of rhombus` = 6 xx 4 cm^2`
Area of rhombus` = 24 cm^2`.
Given one of the diagonal is of length 8 cm, Let `d_1 = 8 cm`.
Let the length of the other diagonal be `d_2`.
If `d_1, d_2` length of the diagonals are known, then Area of rhombus is given by `A = 1/2xxd_1xxd_2`,
But we know, A = 24
Hence, `1/2xxd_1xxd_2= 24`
`1/2xx8xxd_2 = 24`
`d_2= 6 cm`.