Diagram of the adjacent picture frame has outer dimensions `=24cm xx 28cm.` inner dimensions `16cm xx 20cm.` Find the area of each section of the frame, if the width of each section is same.

Explanation

1536891 Let x be width of section .
`BC=x+20+x`
`implies 28=2x+20`
`implies 28-20=2x`
`implies x=4cm`.
We know that ,
Area of section `(1) =(1/2)xx`(sum of parallel sides)`xx` height
`=(1/2)xx(28+20)xx4`
`=(1/2)xx48xx4`
`=96cm^2`
Area of the section `(3)=(1/2)xx(24+16)xx4`
`=(1/2)xx(40)xx2`
`=80cm^2 ` .
Hence ,Area section`(1) =`area section `(2)=96cm^2` and area of section `(3)=`area of section `(4)=80cm^2`.