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Find the height of a trapezium, the sum of the lengths of whose base (parallel sides) is 60cm and whose area is `600\ c m^2dot` .

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Let h be the height of trapezium.
Given
Sum of bases of trapezium `=b1+b2=60cm`.
area of trapezium `=600cm^2`
` implies 600=(1/2)xx(b1+b2)xxh`.
`implies 600=(1/2)xx60xxh`.
`implies h=(600/60)xx2`.
`implies h=20cm`.
Therefore ,height of trapezium`=20cm`.
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