Find the surface area of a chalk box whose length, breadth and height are `16c m ,8c ma n d6c m ,` respectively.

Explanation

Given:
Length of the chalk box `(l)=16cm`
Breadth of the chalk box `(b)=8cm`
Height of the chalk box `(h)=6cm`
We have to find total surface area of the chalk box`=TSA`
Now, we know that
`TSA=2(lb+bh+lh)`
`TSA=2{(16cmtimes8cm)+(8cmtimes6cm)+(6cmtimes16cm)}`
`TSA=2times(128cm^2+48cm^2+96cm^2`)
`TSA=2times272cm^2`
`TSA=544cm^2`
Hence, the total surface area of the chalk box is `544cm^2`.