A cuboid has total surface area of the `40\ m^2` and its lateral surface area is `26\ m^2` . Find the area of its base.

Explanation

Total surface area`=2(lb+bh+hl)=40`
`=(lb+bh+hl)=40/2 m^2`
`=lb+bh+hl=20m^2` .........(1)
Lateral surface area`=2(bh+hl)=26m^2`
`=(bh+hl)=26/2m^2`
`=bh+hl=13m^2` ..........(2)
Subtracting equation (2) from equation (1), we get:
`(lb+bh+hl)−(bh+hl)=20−13`
`lb=7m^2`
`therefore` Area of base`=lb=7m^2`