A piece of ductile metal is in the form of a cylinder of diameter `1cm` and length `11 cm`. It is draw into a wire of diameter `1mm`. What will be the length of the wire so formed?

Explanation

It is given in the question that,
Diameter of the wire = `1cm`
Hence, Radius of the wire =` 0.5 cm`
Length of the height of the wire = `11cm`
Hence,The volume of the wire
=`pir^2b`
= `22-:7 xx0.5 xx0.5 xx 11`
= `8.643 cm³`
Now, We know that, The volumes of both the cylinders would be the same.
And, Diameter of the new wire =` 1mm`
= `0.1 cm`
Radius=`0.05cm`
Therefore the new length of the wire would be
=`pir^3`=`8.643xx7-:22xx0.05xx0.05`=`1100.02cm`
=`11m