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In the given figure, AB is diameter of a...

In the given figure, AB is diameter of a circle with centre O and AT is a tangent at `angleAOQ=58^@`, find `angleATQ`.

Text Solution

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`/_ATQ=?`
`/_ABT=1/2/_AOQ`
`/_ABT=1/2xx58^@`
`=29^@`
`/_ABT=29^@`
In`/_ABT`
`/_A+/_B+/_T=180^@`
`90+29+/_T=180^@`
...
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