In triangle `ABC` `(a^2-b^2-c^2)tanA+(a^2-b^2+c^2)tanB=`

In a triangle ABC , (a^2-b^2-c^2) tan A +(a^2-b^2+c^2) tan B is equal to

In a triangle ABC, (a^2-b^2-c^2) tan A+ (a^2-b^2+c^2) tan B is equal to

In a triangle ABC , (a^2-b^2-c^2) tan A +(a^2-b^2+c^2) tan B is equal to

In a triangle A B C ,\ (a^2-b^2-c^2)tanA+(a^2-b^2+c^2)tanB is equal to (a^2+b^2-c^2)tanC (b) (a^2+b^2+c^2)tanC (b^2+c^2-a^2)tanC (d) none of these

In a triangle A B C ,\ (a^2-b^2-c^2)tanA+(a^2-b^2+c^2)tanB is equal to (a^2+b^2-c^2)tanC (b) (a^2+b^2+c^2)tanC (b^2+c^2-a^2)tanC (d) none of these

In a DeltaA B C , prove the following : (c^2-a^2+b^2)tanA=(a^2-b^2+c^2)tanB=(b^2-c^2+a^2)tanC

In Delta ABC prove that ( a^2 -b^2 + c^2) tanB = (a^2 + b^2 - c^2) tanC

With usual notation show that (c^2-a^2+b^2)tanA = (a^2-b^2+c^2)tanB = (b^2-c^2+a^2)tanC

In any DeltaABC , prove that (c^(2)-a^(2)+b^(2))tanA=(a^(2)-b^(2)+c^(2))tanB=(b^(2)-c^(2)+a^(2))tanC

In a triangle ABC, C=90^@ . Then (a^2-b^2)/(a^2+b^2) =