In triangle `ABC, a=5, b=4` and `cos(A+B)=(31)/(32)` In this triangle,`c=`

If in Delta ABC,a=5,b=4 and cos(A-B)=(31)/(32) ,then

In a triangle ABC, a (b cos C - c cos B) =

In a triangle ABC, a (b cos C - c cos B) =

If in a triangle ABC , a= 5 , b=4 , A = (pi)/(2) +B, then C:

In DeltaABC, if a =5,b=4 and cos (A-B)=31/32 ,then the perimeter of triangle is

In a triangle ABC, a[b cos C - c cos B]=

If in a triangle ABC , a=5,b=4 ,A = (pi)/( 2) +B then C

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.