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The vertices of a DeltaABC are A(4,6), B...

The vertices of a `DeltaABC` are A(4,6), B(1,5) and C(7,2). A line is drawn to intersect sides AB and AC at D and E respectively, such that `(AD)/(AB)=(AE)/(AC)=1/4` Calculate the area of the `DeltaA DE` and compare it with the area of `DeltaABC`

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