" If "x=sec theta-cos theta,y=sec^(n)theta-cos^(n)theta," then "((dy)/(dx))^(2)

If x=sectheta-costheta,y=sec^(n)theta-cos^(n)theta , then ((dy)/(dx))^(2) is :

If x = sec theta - cos theta and y = sec^(n) theta - cos^(n) theta then ((dy)/(dx))^2 is equal to

If x=sec theta-cos theta, y =sec^(n)theta-cos^(n) theta and (x^(2)+4)((dy)/(dx))^(2)=k(y^(2)+4) then the value of k is -

If x = sec theta - cos theta , y= sec^(n)theta - cos^(n) theta then ((x^2+4)/(y^2+4))((dy)/(dx))^2 =

If x=sec theta-cos theta and y=sec^(n)theta-cos^(n)theta then show that (x^(2)+4)((dy)/(dx))^(2)=n^(2)(y^(2)+4)

If x=2cos theta -cos 2theta ,y=2sin theta -sin 2theta ,then (dy)/(dx) =