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16x^(2)-(10)/(x)=27...

16x^(2)-(10)/(x)=27

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Solve by factorization: 16x-(10)/(x)=27

Solve by factorization: 16 x-(10)/x=27

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x^(2)-10x+16

The quadratic equation whose roots are sin^(2)18^(0)&cos^(2)36^(0) is (А) 16x^(2)-12x+1,=0 (В) 16x^(2)+12x+1=0 (C) 16x^(2)-12x-1=0 (D) 16x^(2)-10x-1=0