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If x=sqrt(6) and y^(2)=12, then (4)/(xy)...

If `x=sqrt(6) and y^(2)=12`, then `(4)/(xy)=`

A

`(3)/(2sqrt(2))`

B

`(sqrt(2))/(3)`

C

`(3)/(sqrt(2))`

D

`(2sqrt(2))/(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we need to find the value of \( \frac{4}{xy} \) given that \( x = \sqrt{6} \) and \( y^2 = 12 \). ### Step 1: Determine the value of \( y \) We know that \( y^2 = 12 \). To find \( y \), we take the square root of both sides: \[ y = \sqrt{12} \] We can simplify \( \sqrt{12} \): \[ \sqrt{12} = \sqrt{4 \times 3} = \sqrt{4} \times \sqrt{3} = 2\sqrt{3} \] Thus, \( y = 2\sqrt{3} \) or \( y = -2\sqrt{3} \) (since the square root can be positive or negative). ### Step 2: Substitute the values of \( x \) and \( y \) into \( xy \) Now, we substitute the values of \( x \) and \( y \): \[ x = \sqrt{6} \quad \text{and} \quad y = 2\sqrt{3} \] Calculating \( xy \): \[ xy = \sqrt{6} \times 2\sqrt{3} = 2 \times \sqrt{6} \times \sqrt{3} = 2 \times \sqrt{18} = 2 \times 3\sqrt{2} = 6\sqrt{2} \] ### Step 3: Calculate \( \frac{4}{xy} \) Now we can find \( \frac{4}{xy} \): \[ \frac{4}{xy} = \frac{4}{6\sqrt{2}} = \frac{2}{3\sqrt{2}} \] ### Step 4: Rationalize the denominator To simplify \( \frac{2}{3\sqrt{2}} \), we can rationalize the denominator: \[ \frac{2}{3\sqrt{2}} \times \frac{\sqrt{2}}{\sqrt{2}} = \frac{2\sqrt{2}}{3 \times 2} = \frac{\sqrt{2}}{3} \] ### Final Answer Thus, the value of \( \frac{4}{xy} \) is: \[ \frac{\sqrt{2}}{3} \]
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