If `0.25y+0.36=0.33y-1.48`, what is the value of `(y)/(10)`?

Options

A. `2.30`
B. `1.40`
C. `0.75`
D. `0.64`

Answer

To solve the equation \(0.25y + 0.36 = 0.33y - 1.48\) and find the value of \(\frac{y}{10}\), we can follow these steps:

### Step 1: Rearrange the equation
First, we need to move all terms involving \(y\) to one side and constant terms to the other side. We can do this by subtracting \(0.25y\) from both sides and adding \(1.48\) to both sides.

\[ 0.25y + 0.36 - 0.25y = 0.33y - 1.48 + 1.48 \]

This simplifies to:

\[ 0.36 = 0.33y - 1.48 + 1.48 \]

Which further simplifies to:

\[ 0.36 = 0.33y - 1.48 + 1.48 \implies 0.36 = 0.33y + 0 \]

### Step 2: Combine like terms
Now, we can simplify the equation to:

\[ 0.36 = 0.33y - 1.48 \]

Now, we can move \(1.48\) to the left side:

\[ 0.36 + 1.48 = 0.33y \]

Calculating the left side gives:

\[ 1.84 = 0.33y \]

### Step 3: Solve for \(y\)
To isolate \(y\), we divide both sides by \(0.33\):

\[ y = \frac{1.84}{0.33} \]

Calculating this gives:

\[ y \approx 5.58 \]

### Step 4: Find \(\frac{y}{10}\)
Now, we need to find the value of \(\frac{y}{10}\):

\[ \frac{y}{10} = \frac{5.58}{10} = 0.558 \]

### Final Answer
Thus, the value of \(\frac{y}{10}\) is approximately \(0.558\).