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If 7 questors and n nickels is quivalent...

If 7 questors and n nickels is quivalent to 380 pennies, what is the value of n?

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To solve the problem, we need to express everything in terms of pennies and then set up an equation to find the value of \( n \). ### Step-by-Step Solution: 1. **Understand the values of coins**: - A penny is worth 1 cent. - A nickel is worth 5 cents, which is equivalent to 5 pennies. - A quarter is worth 25 cents, which is equivalent to 25 pennies. 2. **Calculate the total value of 7 quarters in pennies**: \[ \text{Value of 7 quarters} = 7 \times 25 \text{ pennies} = 175 \text{ pennies} \] 3. **Express the value of \( n \) nickels in pennies**: \[ \text{Value of } n \text{ nickels} = n \times 5 \text{ pennies} = 5n \text{ pennies} \] 4. **Set up the equation based on the problem statement**: According to the problem, the total value of 7 quarters and \( n \) nickels is equivalent to 380 pennies: \[ 175 + 5n = 380 \] 5. **Solve for \( n \)**: - First, subtract 175 from both sides: \[ 5n = 380 - 175 \] \[ 5n = 205 \] - Now, divide both sides by 5: \[ n = \frac{205}{5} = 41 \] 6. **Conclusion**: The value of \( n \) is \( 41 \).
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