If `s+3s` is 2 more than `t+3t`, then `s-t=`

Options

A. `-2`
B. `-(1)/(2)`
C. `(1)/(2)`
D. `(3)/(4)`

Answer

To solve the equation given in the problem, we will follow these steps:

1. **Understand the equation**: The problem states that \( s + 3s \) is 2 more than \( t + 3t \). We can express this mathematically.

2. **Write the equation**:
\[ s + 3s = (t + 3t) + 2 \]

3. **Combine like terms**:
- On the left side, \( s + 3s \) simplifies to \( 4s \).
- On the right side, \( t + 3t \) simplifies to \( 4t \).
Therefore, the equation becomes:
\[ 4s = 4t + 2 \]

4. **Rearrange the equation**:
- To isolate \( s \) and \( t \), we can subtract \( 4t \) from both sides:
\[ 4s - 4t = 2 \]

5. **Factor out the common term**:
- We can factor out 4 from the left side:
\[ 4(s - t) = 2 \]

6. **Divide both sides by 4**:
\[ s - t = \frac{2}{4} \]

7. **Simplify the fraction**:
\[ s - t = \frac{1}{2} \]

Thus, the final answer is:
\[ s - t = \frac{1}{2} \]