Home
Class 10
MATHS
If 2p+q=11 and p+2q=13, then p+q=...

If `2p+q=11 and p+2q=13,` then p+q=

A

`6`

B

`8`

C

`9`

D

`12`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equations \(2p + q = 11\) and \(p + 2q = 13\) and find the value of \(p + q\), we can follow these steps: ### Step 1: Write down the equations We have: 1. \(2p + q = 11\) (Equation 1) 2. \(p + 2q = 13\) (Equation 2) ### Step 2: Multiply Equation 1 by 2 To eliminate \(q\), we can multiply Equation 1 by 2: \[ 2(2p + q) = 2(11) \] This gives us: \[ 4p + 2q = 22 \quad (Equation 3) \] ### Step 3: Subtract Equation 2 from Equation 3 Now we will subtract Equation 2 from Equation 3: \[ (4p + 2q) - (p + 2q) = 22 - 13 \] This simplifies to: \[ 4p + 2q - p - 2q = 9 \] So we have: \[ 3p = 9 \] ### Step 4: Solve for \(p\) Now, divide both sides by 3: \[ p = \frac{9}{3} = 3 \] ### Step 5: Substitute \(p\) back into one of the original equations We can substitute \(p = 3\) into Equation 1: \[ 2(3) + q = 11 \] This simplifies to: \[ 6 + q = 11 \] Now, solve for \(q\): \[ q = 11 - 6 = 5 \] ### Step 6: Find \(p + q\) Now that we have \(p\) and \(q\): \[ p + q = 3 + 5 = 8 \] ### Final Answer Thus, the value of \(p + q\) is \(8\). ---
Promotional Banner

Topper's Solved these Questions

  • HEART OF ALGEBRA

    ENGLISH SAT|Exercise Grib-In|62 Videos

Similar Questions

Explore conceptually related problems

If f(x) = px +q, where p and q are integers f (-1) = 1 and f (2) = 13, then p and q are

If p != 0, q != 0 and the roots of x^(2) + px +q = 0 are p and q, then (p, q) =

If p and q are positive, p^2 + q^2 = 16 , and p^2 - q^2 = 8 , then q =

If p= q + 2 then p gt q .

If p , qr are real and p!=q , then show that the roots of the equation (p-q)x^2+5(p+q)x-2(p-q=0 are real and unequal.

If p ,q are real p!=q , then show that the roots of the equation (p-q)x^2+5(p+q)x-2(p-q)=0 are real and unequal.

If p and q are the roots of the equation x^2-p x+q=0 , then (a) p=1,\ q=-2 (b) p=1,\ q=0 (c) p=-2,\ q=0 (d) p=-2,\ q=1

If one root is square of the other root of the equation x^2+p x+q=0, then the relation between pa n dq is p^3-q(3p-1)+q^2=0 p^3-q(3p+1)+q^2=0 p^3+q(3p-1)+q^2=0 p^3+q(3p+1)+q^2=0

If two positive integers a and b are expressible in the form a=p q^2 and b=p^3q ; p ,\ q being prime numbers, then LCM (a ,\ b) is (a) p q (b) p^3q^3 (c) p^3q^2 (d) p^2q^2

Given that P 12, Q = 5 and R = 13 also P+Q=R, then the angle between P and Q will be