Chelsea has $45 to spend at an amusement park.She spends $20 on admission and $15 on snacks. She wants to play a game that costs $0.65 per game. What is the maximum number of times she can play the game?

Answer

To solve the problem step by step, we will break it down into parts:

**Step 1: Determine the total amount Chelsea has.**
Chelsea has a total of $45.

**Step 2: Calculate the amount spent on admission and snacks.**
Chelsea spends $20 on admission and $15 on snacks.

**Step 3: Calculate the total amount spent.**
Total spent = Amount on admission + Amount on snacks
Total spent = $20 + $15 = $35

**Step 4: Calculate the remaining amount.**
Remaining amount = Total amount - Total spent
Remaining amount = $45 - $35 = $10

**Step 5: Determine the cost per game.**
The cost to play one game is $0.65.

**Step 6: Calculate the maximum number of games she can play.**
Maximum number of games = Remaining amount / Cost per game
Maximum number of games = $10 / $0.65

**Step 7: Perform the division.**
To find out how many times she can play the game:
Maximum number of games = 10 / 0.65 ≈ 15.38

Since Chelsea cannot play a fraction of a game, we round down to the nearest whole number:
Maximum number of games = 15

Therefore, the maximum number of times Chelsea can play the game is **15**.

---