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A function f is defined such that f(1)=2...

A function f is defined such that `f(1)=2, f(2)=5, and f(n)=f(n-1)-f(n-2)` for all integer values of n greater than 2. What is the value of f(4)?

A

`-8`

B

`-2`

C

`2`

D

``

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( f(4) \) given the function defined by the rules: 1. \( f(1) = 2 \) 2. \( f(2) = 5 \) 3. \( f(n) = f(n-1) - f(n-2) \) for all integers \( n > 2 \) we will follow these steps: ### Step 1: Find \( f(3) \) Using the recursive formula for \( n = 3 \): \[ f(3) = f(3-1) - f(3-2) = f(2) - f(1) \] Substituting the known values: \[ f(3) = f(2) - f(1) = 5 - 2 = 3 \] ### Step 2: Find \( f(4) \) Now, we can find \( f(4) \) using the recursive formula for \( n = 4 \): \[ f(4) = f(4-1) - f(4-2) = f(3) - f(2) \] Substituting the values we have: \[ f(4) = f(3) - f(2) = 3 - 5 = -2 \] ### Final Answer Thus, the value of \( f(4) \) is: \[ \boxed{-2} \]
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