18.5 + 6y = 13, 3 + 4y = 7 (x=0).

( 5)/(x) + 6y = 13, (3)/(x) + 4y = 7 ( x ne 0 )

6x - 5y - 16 = 0 , 7x - 13 y + 10 = 0 .

Show that the equations 5x + 6y = 3 = 0 and 4y + x = 5 are consistent and hence, solve for x and y.

0.3x + 0.7y = .13 0.4x + 0.5y = .13

5x - 4y + 8 = 0 7x + 6y - 9= 0

If the equations of the tangent to the circle x^(2)+ y^(2)- 2x + 6y -6 =0 parallel to 3x - 4y + 7=0 is 3x - 4y +k=0 , then the values of k are : a) 5,-35 b) -5,35 c) 7,-32 d) -7,32

The equation of the line passing through the intersection of the lines 3x + 4y = -5, 4x + 6y = 6 and perpendicular to 7x - 5y + 3 = 0 is :

The equation of the line passing through the intersection of the lines 3x + 4y = -5, 4x + 6y = 6 and perpendicular to 7x - 5y + 3 = 0 is :

The equation to a pair of opposite sides of a parallelogram are x^2-5x+6=0 and y^2-6y+5=0 . The equations to its diagonals are (a) x+4y=13 ,y=4x-7 (b) 4x+y=13 ,4y=x-7 (c) 4x+y=13 ,y=4x-7 (d) y-4x=13 ,y+4x-7

If [2x+y,4x,5x-7 4x]=[7 7y-13 y x+6] , then the value of x+y is x=3 , y=1 (b) x=2 , y=3 (c) x=2 , y=4 (d) x=3 , y=3