Let `tan(alpha+beta)=4/5` and `tan(alpha-beta)=3/5` then correct option is

If 2tan alpha=3tan beta then tan(alpha-beta)=

If 0<=alpha,beta<=90^(@) and tan(alpha+beta)=3 and tan(alpha-beta)=2 then value of sin2 alpha is

Let cos(alpha+beta) =4/5 and let sin (alpha-beta)=5/13 where 0 le alpha, beta le (pi)/(4) then tan 2 alpha

Let cos(alpha+beta)=(4)/(5) and let sin(alpha-beta)=(5)/(13) , where 0 le alpha , beta=(pi)/(4) . Then tan2alpha=

If sin(alpha + beta) = 4/5 and sin (alpha - beta)= 5/13 , find the value of tan 2 alpha .

Let cos (alpha+beta) = 4/5 and sin(alpha-beta)=5/13 where 0<= alpha,beta<= pi/4 then find tan (2alpha)

If tan (alpha+beta)=a+b and tan(alpha-beta)=a-b,thenshowtâtan alpha-b tan beta=a^(2)