A prism `(mu=1.5)` has the refracting angle of `30^(@)` The deviation of a monochromatic ray incident normally on its one surface will be `(sin 48^(@) 36 = 0.75)`

A prism (mu = 1.5) has the refracting angle of 30^(@) . The deviation of a monochromatic ray incident normally on its one surface will be [sin 48^(@)36' = 075]

A prism (mu = 1.5) has the refracting angle of 30^(@) . The deviation of a monochromatic ray incident normally on its one surface will be [sin 48^(@)36' = 075]

A prism having refractive index sqrt(2) and refracting angle 30^(@) , has one of the refracting surfaces polished. A beam of monochromatic light incident on the other refracting surface will retrace its path if the angle of incidence is

A prism having refractive index sqrt(2) and refracting angle 30^(@) , has one of the refracting surfaces polished. A beam of monochromatic light incident on the other refracting surface will retrace its path if the angle of incidence is

If the refracting angle of a prism is A, the refractive index of its material is mu and the angle of deviation of a ray of light incident normally on the first refraction face is delta , then prove that mu = sin(A + delta)/(sinA).

There is an equilateral prism of material of refractive index 1.5. Light ray is incident normally on its surface. What will be the angle of deviation of ray ?

A Ray of light is incident at an angle 60° on one face of a prism which has protecting angle of 30°. The emerging ray deviates through 30° from incident light. The refractive index of material of prism is

A Ray of light is incident at an angle 60° on one face of a prism which has protecting angle of 30°. The emerging ray deviates through 30° from incident light. The refractive index of material of prism is

A ray of light incident at an angle of 48^(@) is refracted through a prism in its position of minimum deviation. The angle of prism is 60^(@) . Calculate the refractive index of the material of the prism. (sin 48^(@) = 0.74, sin 30^(@) = 0.50)