The time of fight of an object projected with speed ` 20 ms^(-1)` at an angle ` 30^(@)` with the horizontal , is

The maximum height attained by a ball projected with speed 20 ms^(-1) at an angle 45^(@) with the horizontal is [take g = 10 ms^(-2) ]

The maximum height attained by a ball projected with speed 20 ms^(-1) at an angle 45^(@) with the horizontal is [take g = 10 ms^(-2) ]

A particle is projected from the surface of the earth with a speed of 20 m* s^(-1) at an angle 30^@ with the horizontal . The time of flight of that particle is

A stone is projected with speed of 50 ms^(-1) at an angle of 60^(@) with the horizontal. The speed of the stone at highest point of trajectory is

A stone is projected with speed of 50 ms^(-1) at an angle of 60^(@) with the horizontal. The speed of the stone at highest point of trajectory is

A particle is projected from the surface of the earth with a speed of 20 m* s^(-1) at an angle 30^@ with the horizontal . The range of that particle is

An object is projected with a velocity of 30 ms^(-1) at an angle of 60^(@) with the horizontal. Determine the horizontal range covered by the object.

An object is projected with a velocity of 30 ms^(-1) at an angle of 60^(@) with the horizontal. Determine the horizontal range covered by the object.

A particle is projected with a speed 10sqrt(2) ms^(-1) and at an angle 45^(@) with the horizontal. The rate of change of speed with respect to time at t = 1 s is (g = 10 ms^(-2))