In `triangle ABC` if `cot (A/2):cot (B/2): cot (C/2)=3:5:7` then a:b:c?

In a triangle ABc , if r^2cot(A/2) cot(B/2) cot(C/2)=

In Delta ABC, if cot""A/2:cot""B/2:cot""C/2=3:7:9 , then a:b:c=

If cot A/2:cot"" B/2: cot"" C/2 = 3:5:7 then show that a:b:c = 6:5:4 .

If Delta ABC , if cot A/2 , cot B/2 : cot C/2 = 4:3:2 , then a : b : c =

In a triangle ABC if cot(A/2)cot(B/2)=c, cot(B/2)cot(C/2)=a and cot(C/2)cot(A/2)=b then 1/(s-a)+1/(s-b)+1/(s-c)=

In a triangle ABC if cot(A/2)cot(B/2)=c, cot(B/2)cot(C/2)=a and cot(C/2)cot(A/2)=b then 1/(s-a)+1/(s-b)+1/(s-c)=

In a triangle ABC,if a cot A+b cot B+c cot C=

In a triangle ABC, if r^(2)cot((A)/(2))cot((B)/(2))cot((C)/(2))=

In a Delta ABC, if cot((A)/(2)):cot((B)/(2)):cot((C)/(2))=1:4:15 then the greatest angle is