An open merry-go-round rotates at an angular velocity `omega`. A person stands in it at a distance r from the rotational axis. It is raining, and the raindrops fall vertically at a velocity `v_(0)`. How should the person hold an umbrella to protect himself from the rain in teh best way ?

An open merry go round rotates at an angular velocity omega .A person stands in it at a distance r from the rotational axis.It is raining and the rain drops falls vertically at a velocity v_(0) .How should the person hold an umbrella to prorect himself from the rain in the best way.Angle made by umbrealla with the vertical is

A man walking on a road with a velocity of 5 km per hour encounters rain falling vertically with a velocity of 25 km per hour. At what angle should he holds his umbrella in order to protect himself form the rain?

A man is going due east with a velocity of 5ms^(-1) .It is vertically rainging downwards with a velocity of 4ms^(-1) .At what angle should he hold the umbrella to the vertical so as to protect him self from the rain?

A boy is running on a horizontal road with a velocity of 5 m/s. At what angle should he hold his umbrella in order to protect him self from the rain if the rain is falling vertically with a velocity of 10 m/s?

A man is going due east with a velocity of 3 kmh^(-1) . Rain falls vertically downwards at a speed of 10 km h^(-1) . Calculate the angle at which he should hold his umbrella so as to protect himself from rain.

By the term velocity of rain, we mean velocity with which raindrops fall relative to the ground. In absence of wind, raindrops fall vertically and in presence of wind raindrops fall obliqucly. Moreover raindrops acquire a constant terminal velocity due air resistance very quickly as they fall toward the carth. A moving man relative to himself observes an altered velocity of raindrops. Which is known as velocity of rain relative to the man. It is given by the following equation. vec(v)_(rm)=vec(v)_(r)-vec(v)_(m) A standstill man relative to himself observes rain falling with velocity, which is equal to velocity of the raindrops relative to the ground. To protect himself a man should his umbrella against velocity of raindrops relative to himself as shown in the following figure. Rain is falling vertically with velocity 80 cm/s. (a) How should you hold your umbrella ? (b) You start walking towards the east with velocity 60 cm/s. How should you hold umbrella ? (c) You are walking towards the west with velocity 60 cm/s. How should you hold your umbrella ? (d) You are walking towards the north with velocity 60 cm/s. How should you hold your umbrella? (e) You are walking towards the south with velocity 80 cm/s. How should you hold your umbrella ?

It is raining at a speed of 5m//s^(-1) at an angle 37^(@) to vertical, towards east. A man is moving to west with a velocity of 5 m//s^(-1) .The angle with the vertical at which he has to hold the umbrella to protect himself from rain is.

A rigid body of mass m rotates with angular velocity omega about an axis at a distance a from the centre of mass G. The radius of gyration about a parallel axis through G is k. The kinetic energy of rotation of the body is

Find the mass of a mole of colloid particles if during their centrifuging with an angular velocity omega about a vertical axis the concentration of the particles at the distance r_2 from the rotation axis is eta times greater than that at the distance r_1 (in the same horizontal plane). The densities of the particles and the solvent are equal to rho and to rho_0 respectively.