Total kinetic energy of molecules of a gas sample varies `K.E.=(7)/(4)nRT`. This sample contains

The mean translational kinetic energy of a molecule of an ideal gas at temperature T K is

Total random kinetic energy of the molecules in 1 mole of a gas at a temperature of 300 K is (R = 2 cal/mole °C)

Total random kinetic energy of the molecules in 1 mole of a gas at a temperature of 300 K is (R = 2 cal/mole °C)

The average kinetic energy of the molecules of an ideal gas at 10 ^@ C has the value (E). The temperature at which the kinetic energy of the same gas becomes (2 E) is.

The average kinetic energy of the molecules of an ideal gas at 10 ^@ C has the value (E). The temperature at which the kinetic energy of the same gas becomes (2 E) is.

The kinetic energy of N molecules of O_(2) is x joule at -123^(@)C . Another sample of O_(2) at 27^(@) C has a kinetic energy of 2x. The latter sample contains molecules of O_(2) .

Prove that c_(rms)=sqrt((2E)/(M)) [E=total kinetic energy of the molecules of 1 mol of a gas, M=molar mass of the gas, c_(rms)= root mean square velocity of gas molecule].

Two gases O_2 and H_2 are at the same temperature . If E_o is the average kinetic energy of a molecule of oxygen sample , and E_H is the average kinetic energy of a molecule of hydrogen sample , then