A particle is projected from level ground its kineitc energy K changes due to gravity so that `K_("max")//K_("min")=9`. The ratio of the range to the maxir, un height attained during its fight is

A particle is projected at 60 ^@ to the horizontal with kinetic energy K. Its kinetic energy at the highest point is :

A particle is projected at 60 ^@ to the horizontal with kinetic energy K. Its kinetic energy at the highest point is :

A particle is projected with a velocity u so that its horizontal range is twice the greatest height attained. The horizontal range is

A particle is projected with a velocity v so that its horizontal range twice the greatest height attained. The horizontal range is

A particle is projected with a velocity v so that its horizontal range twice the greatest height attained. The horizontal range is

A particle is projected from the ground with speed u un such a manner that its range is found to be two times the maximum height . If range of the projectile can be written as ("nu"^(2))/(5g) , then what is the value of n ?

A particle of mass m is projected from the ground with initial linear momentum p (magnitude) such that to have maximum possible range, its minimum kinetic energy will be