If `T_1 and T_2` are the times of flight for two complementary angles, then the range of projectile R is given by

A projectile has the same range R for two angles of projections but same speed. If T_(1) and T_(2) be the times of flight in the two cases, then Here theta is the angle of projection corresponding to T_(1) .

A projectile has the same range R for angles of projections. If T_(1) and T_(2) be the times of fight in the two cases, then ( using theta as the angle of projection corresponding to T_(1) )

A projectile has the same range R for angles of projections. If T_(1) and T_(2) be the times of fight in the two cases, then ( using theta as the angle of projection corresponding to T_(1) )

A projectile can have the same range R for two angle of projection . If t-1 and t_2 be the terms of flight in the two cased then the initial velocity of projectile is?

A projectile can have the same range R for two angles of projection. If t_1 and t_2 are the times of flight in the two cases, then the product of the two time of flight is proportional to A. R^2 B. frac(1)(R^2) C. frac(1)(R) D. R

A projectile can have the same range R for two angles of projection .If t_1 and t_2 be the times of flight in the two cases, then the product of the two times of fight is directly proportional to

A projectile can have same range R for two angles of projection. It t_1 and t_2 are the times of flight in the two cases, then what is the product of two times of flight ?

A projectile can have same range R for two angles of projection. It t_1 and t_2 are the times of flight in the two cases, then what is the product of two times of flight ?

If the time of flight of a bullet over a horizontal range R is T, then the angle of projection with horizontal is -