29" of "S" is heated to occupy a volume of "780ml" at "450^(@)C" and "723mm" pressure.Formula of sulphur is "

3.2 g of S is heated to occupy a volume of 780 ml at 450^(@)C and 723 mm pressure. Formula of sulphure is

When 3.2g of sulphur is vapourised at 450^(@)C and 723 mm pressure , the vapours occupy a volume of 780ml. What is the molecular formula of sulphur vapours under these conditions? Calculate the vapour density also.

If 3.2 g of sulphur is heated to a temperature, the sulphur vapour produced occupies a volume of 780 mL at 723 mm pressure and 450^(@)C . What is the molecular formula of sulphur at this state?

When 3.2gm of sulphur is vapourised,it gives 280ml of vapour at 273^(@)C and 1520mm pressure.Molecular formula of sulphur is

A certain mass of a gas occupies a volume of 300 c.c. at 27^(@)C and 620 mm pressure. The volume of this gas at 47^(@)C and 640 mm pressure will be "______________" .

When 3.2 g S is vaporized at 450^(@)C and 723 mm pressure, the vapours occupy a volume of 780 mL What is the molecular formula of S vapours ?