A particle is projected with `20ms^(-1)` at `30^(@)` above horizontal. Find ratio of maximum height to the range of the projectile.

In the horizontal projection, the range of the projectile is

A particle is projected with velocity u at angle theta_(1) with horizontal .The ratio of range and maximum height is 4. When it is projected at angle theta_(2) with horizontal with same speed,the ratio of range and maximum height is 2.Then (tan theta_(1))/(tan theta_(2)) will be equal to

Two projectiles are projected with the same velocity. If one is projected at an angle of 30^(@) and the other at 60^(@) to the horizontal, then ratio of maximum heights reached, is

A projectile is thrown with a speed of 98 ms^(-1) in a direction 30^(@) above the horizontal . Find the time of flight , range and height to which it rises .

A particle is projected at an angle of tan^(-1)(4/3) with horizontal from a point O.The ratio of the range on the horizontal plane through O to the maximum height ascended above O is

A body is projected with a velocity of 30 ms^(-1) at an angle of 30^(@) with the vertical. Find the maximum height, time of flight and the horizontal range.

Two projectile are projected with the same velocity. If one is projected at an angle of 30^(@) to the horizontal. The ratio if maximum heights reached, is: