Heat of neutralisation of `NaOH` and `HCl` is `-57.46 kJ //` equivalent. The heat of ionisation of water in `kJ //mol` is `:`

The heat of neutralization of NaOH with HCl is 57.3 KJ and with HCN is 12.1 KJ. The heat of ionization of HCN is

The heat of neutralization of NaOH with HCl is 57.3 KJ and with HCN is 12.1 KJ. The heat of ionization of HCN is

Heat of neutralisation of H_2SO_4 with NaOH is - x KJ. Then the heat of ionisation of water is

The heat of neutralization of LiOH and HCI at 25 ^(@)C is -34.868 kJ mol^(-1) . The heat of ionisation of LiOH will be

The heat of neutralisation of acetic and NaOH is 55.9 kJ. If the heat of neutralisation of all strong acids and strong bases is 57.3 kJ, then calculate the heat of ionisation of acetic acid.

The heat of neutralization of LiOh and HCI at 25 ^(@)C is 34.868 kJ mol^(-1) . The heat of ionisation of LiOh will be

The heat of neutralisation of HCl by NaOH is-55.9 kJ/mol. If the heat of neutralisation of HCN by NaOH is -12.1 kJ/mol. The energy of disso-ciation of HCN is: