`1.0 g` of `Mg "atom" ("atomic mass" = 24.0 ama)` in the vapour phase abserbe `50.0 kJ` energy .Find the composition of the final maximum if the first and the second if of Mg are `740 kJ "mol^(-1)` respectively

1.0 g of Mg "atom" ("atomic mass" = 24.0 "amu") in the vapour phase absorbs 50.0 kJ energy .Find the composition of the final maximum if the first and the second if of Mg are 740 kJ "mol^(-1) respectively

1.0 g of Mg "atom" ("atomic mass" = 24.0 "amu") in the vapour phase absorbs 50.0 kJ energy .Find the composition of the ions if the first and the second IE of Mg are 740 kJ and 1450 "mol^(-1) respectively

1g of Mg atoms in the vapour phase absorbs 50.0KJ of energy find the percentage composition of Mg^+ and Mg^(+2) formed as a result of absorption of energy IE_1 and IE_2 for Mg are 740 and 1450kjmol^(-1) respectively

One mole of magnesium in the vapor state absorbed 1200 kJ mol^(-1) of enegry. If the first and second ionization energies of Mg are 750 and 1450 kJ mol^(-1) , respectively, the final composition of the mixture is

One mole of magnesium in the vapor state absored 1200 kJ mol^(-1) of enegry. If the first and second ionization energies of Mg are 750 and 1450 kJ mol^(-1) , respectively, the final composition of the mixture is

One mole of magnesium in the vapour state absorbed 1200 kJ 'm o l^(-1)' of energy. If the first and second ionization energies of 'Mg' are 750 and '1450 kJ mol^(-1)' respectively, the final composition of the mixture is

Correct order of first ionization energy of the following metals Na, Mg, Al, Si in kJ mol^(–1) respectively are: