[" Let "A=|[2,b,1],[b,b^(2)+1,b],[1,b,2]|" where "b>0],[" then the minimum value of "(det(A))/(b)],[" is "]

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A=[(2,b,1),(b,b^(2)+1,b),(1,b,2)] where b gt 0 . Then the minimum value of ("det.(A)")/(b) is

Let A = [{:(2, b,1),(b, b^(2)+1,b),(1, b,2):}], " where "b gt 0 . Then, the maximum value of ("det"(A))/(b) is

Let Delta=|(a,a^(2),0),(1,2a+b,(a+b)^(2)),(0,1,2a+3b)| then

Let the matrix A and B be defined as A=[[3 , 2], [ 2 , 1]] and B=[[3, 1],[ 7, 3]] then the absolute value of det. (2 A^9 B^-1) is

Let f(x)=(1+b^2)x^2+2b x+1 and let m(b) be the minimum value of f(x)dot As b varies, the range of m(b) is (a) [0,} b. (0,1/2) c. 1/2,1 d. (0,1]

Let f(x)=(1+b^(2))x^(2)+2bx+1 and let m(b) be the minimum value of f(x). As b varies,the range of m(b) is [0,} b.(0,(1)/(2)) c.(1)/(2),1 d.(0,1]