A particle is projected form a horizontal plane `(x-z` plane) such that its velocity vector at time `t` is gives by `vecV = ahati +(b - ct)hatj`. Its range on the horizontal plane is given by

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

The velocity at the maximum height of a projectile is half of its velocity of projection u . Its range on the horizontal plane is

A particle is projected from the horizontal x-z plane, in vertical x-y plane where x-axis is horizontal and positive y-axis vertically upwards. The graph of y coordinate of the particle v/s time is as shown . The range of the particle is sqrt3 . Then the speed of the projected particle is:

A particle is projected from the horizontal x-z plane, in vertical x-y plane where x-axis is horizontal and positive y-axis vertically upwards. The graph of y coordinate of the particle v/s time is as shown . The range of the particle is sqrt3 . Then the speed of the projected particle is:

A particle is projected from a horizontal plane with a velocity of 8sqrt2 ms ^(-1) ms at an angle theta . At highest point its velocity is found to be 8 ms^(-1) Its range will be (g=10 ms^(-2))

A particle is projected from origin in xy-plane and its equation ,of trajectory is given by y = ax - bx^(2) . The only acceleration ,in the motion is' f' which is constant and in -ve direction of, y-axis. (a) Find the velocity of projection and the angle of projection. (b) Point of projection is considered as origin and x-axis along the horizontal ground. Find the horizontal range: and maximum height of projectile. Projectile completes its flight in horizonal plane of projection.

A particle is projected with a velocity v such that its range on the horizontal plane is twice the greatest height attained by it. The range of the projectile is (where g is acceleration due to gravity)

A particle is projected up an inclines plane. Plane is inclined at an angle theta with horizontal and particle is projected at an angle alpha with horizontal. If particle strikes the plane horizontally prove that tan alpha=2 tan theta

A particle is projected up an inclines plane. Plane is inclined at an angle theta with horizontal and particle is projected at an angle alpha with horizontal. If particle strikes the plane horizontally prove that tan alpha=2 tan theta