If in the previous problem, particle `A` moves with constant acceleration `4 m//s^(2)` with initial speed `5 m//s` and `B` moves with uniform speed `12 m//s`, when and where the particle meet?

In the previous problem if the car is moving with a constant acceleration of 2 m//s^(2) , the ball will fall behind the person at a distance

A body moves from rest with a constant acceleration of 5m//s^(2) . Its instantaneous speed (in m/s) at the end of 10 sec is

two particles A and B are at separation of 100 m . They move towards each other with uniform speed, A with 5 m//s and B with 15 m//s . When and where the two particle meet?

A particle moves rectilinearly with a constant acceleration 1 m//s^2 . Its speed after 10 seconds is 5 m//s . The distance covered by the particle in this duration is.

A particle moves in a circle of radius 4m with a linear speed of 20m//s . Find the angular speed.

A particle is moving on a straight line with constant retardation of 1 m//s^(2) . Its initial velocity is 10 m//s .

A particle is moving with a uniform acceleration 4 m s^(-2) for time 2 second and then 5 m s^(-20 for time 3 seconds . What is the average acceleration of particle during motion.

A particle is initially at rest. It starts moving with a constant acceleration, the speed of the particle in t seconds is 50m/s and after one second the speed becomes 75m/s. calculate the acceleration of the particle and distance covered in (t+1)^("th") second of its motion.