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1.5g of monobasic acid when dissolved in...

`1.5g` of monobasic acid when dissolved in `150g` of water lowers the freezing point by `0.165^(@)C.0.5g` of the same acid when titrated, after dissolution in water, requires `37.5 mL` of `N//10` alkali. Calculate the degree of dissociation of the acid `(K_(f)` for water `= 1.86^(@)C mol^(-1))`.

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1 g of monobasic acid in 100 g of water lowers the freezing point by 0.168^(@) . If 0.2 g of same acid requires 15.1 mL mol^(-1) of N//10 alkali for complete neutralization, calculate the degree of dissociation of acid. K'_(f) for H_(2)O is 1.86 K mol^(-1) kg .

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A solution is prepared by dissolving 1.5g of a monoacidic base into 1.5 kg of water at 300K , which showed a depression in freezing point by 0.165^(@)C . When 0.496g of the same base titrated, after dissolution, required 40 mL of semimolar H_(2)SO_(4) solution. If K_(f) of water is 1.86 K kg mol^(-1) , then select the correct statements (s) out of the following( assuming molarity = molarity):

A solution is prepared by dissolving 1.5g of a monoacidic base into 1.5 kg of water at 300K , which showed a depression in freezing point by 0.165^(@)C . When 0.496g of the same base titrated, after dissolution, required 40 mL of semimolar H_(2)SO_(4) solution. If K_(f) of water is 1.86 K kg mol^(-1) , then select the correct statements (s) out of the following( assuming molarity = molarity):

5 g of a substance when dissolved in 50 g water lowers the freezing by 1.2^(@)C . Calculate molecular wt. of the substance if molal depression constant of water is 1.86 K kg mol^-1 .