6m-(m-1)/(2)=1-(m-2)/(3)

Solve each of the following equation. Also, verify the result in each case. (6x-2)/9+(3x+5)/(18)=1/3 2. m-(m-1)/2=1-(m-2)/3

(m-1)/(m-4)=(2m-3)/(3m-8)

If l : m = 2 (1)/(2) : 1(2)/(3) and m : n = 1 (1)/(4) : 3 (1)/(2) , find l : m : n

Find the value of m ( m -1 )/3 - ( m -2 )/4 = 1

m(m-1)(m-2)...3.2.1=

Find the nth and 6th term of the AP (2m + 1)/m , (2m-1)/m , (2m-3)/m..

The lines y=m_(1)x,y=m_(2)xandy=m_(3)x make equal intercepts on the line x+y=1 Then (a) 2(1+m_(1))(1+m_(3))=(1+m_(2))(2+m_(1)+m_(3))(1+m_(1))(1+m_(3))=(1+m_(2))(1+m_(1)+m_(3))(1+m_(1))(1+m_(2))=(1+m_(3))(2+m_(1)+m_(3))(1+m_(1))(1+m_(3))=(1+m_(2))(1+m_(1)+m_(3))2(1+m_(1))(1+m_(3))=(1+m_(2))(1+m_(1)+m_(3))

Explain, given reasons, which of the following sets of quantum numbers are not possible. (1) n=0,l=0,m_(l)=0,m_(S)+(1)/(2) (2) n=1,l=0,m_(l)=0,m_(S)=-(1)/(2) (3) n=1,l=1,m_(l)=0,m_(S)=+(1)/(2) (4) n=2, l=1, m_(1)=0,m_(S)=-(1)/(2) (5) n=3, l=3, m_(l)=-3,m_(S)=+(1)/(2) (6) n=4, l=1, m_(l)=0,m_(S)=+(1)/(2) .