" (x) "6x^(2)+40=31x

Solve each of the following equatins : 6x^(2)+40=31x

Solve each of the following equatins : 6x^(2)+40=31x

Solve: 6x^(2)+40=31x.

Write the quotient and remainder when we divide : (6x^(2) - 31 x + 47) by (2x - 5)

Find the G.C.D of x^(3) - 10x^(2) + 31x - 30 and 2x^(3) - 8x^(2) + 2x + 12

Solve : (x + 6)(x-6) - (x-5)^(2) = 40 - 17(x-2)

Find the quotient and the remainder when 6x^(2)-31x+47 is divided by (2x-5)

The equation whose roots are reciprocals of the roots of 6x^(6) - 25x^(5) + 31x^(4) - 31x^(2) + 25x - 6 = 0 is