A body of mass `2g`, moving along the positive x-axis in gravity free space with velocity `20cms^-1` explodes at `x=1m`, `t=0` into two pieces of masses `2//3g` and `4/3g`. After `5s`, the lighter piece is at the point `(3m, 2m, -4m)`. Then the position of the heavier piece at this moment, in metres is

A bomb moving with velocity (40i+50j-25k)m//s explodes into two pieces of mass ratio 1:4. After explosion the smaller piece moves away with velocity (200i +70j +15k)m//s . The velocity of larger piece after explosion is .

An isolated particle of mass m is moving in a horizontal plane (x-y), along the x-axis at a certain height above the ground. It suddenly explodes into two fragments of masses m//4 and 3m//4 . At instant later, the smaller fragment is at y = +5 cm . What is the position of larger fragment at this instant ?

A bomb moving with velocity (40hati+50hatj - 25hatk) m/s explodes into two pieces of mass ratio 1 : 4. After explosion the smaller piece moves away with velocity (200hati + 70hatj +15hatk)m//s .

The spacecraft of mass M moves with velocity v in free space at first, then it explodes breaking into two pieces. If after explosion a piece of mass m comes to rest, the other piece of space craft will have a velocity :

A free particle of mass m was in motion along the x-axis on a horizontal x-y plane kept at a fixed height above the earth. On sudden explosion, the particle broke up into two pieces of masses (m)/(4) and (3m)/(4) . After an interval of time, position of the smaller fragment along y-axis become y = 15 cm. At that moment, position of the larger piece was

A bomb of mass 3.0Kg explodes in air into two pieces of masses 2.0 kg and 1.0 kg . The smaller mass goes at a speed of 80 m/s .The total energy imparted to the two fragments is