[F rArr(3x^(2)c+2y)],[" k done by twe force "]

A force F=-(K)/(x^(2))(xne0) acts on a particle along the X-axis . Find the work done by the force in displacing the particale from x = +a to x = + 2a. Take K as a positive constant .

Two curves C_(1)equiv[f(y)]^(2//3)+[f(x)]^(1//3)=0 and C_(2)equiv[f(y)]^(2//3)+[f(x)]^(2//3)=12, satisfying the relation "(x-y)f(x+y)-(x+y)f(x-y)=4xy(x^(2)-y^(2)) The area bounded by the curve C_(1) and C_(2) is

Two curves C_(1)equiv[f(y)]^(2//3)+[f(x)]^(1//3)=0 and C_(2)equiv[f(y)]^(2//3)+[f(x)]^(2//3)=12, satisfying the relation "(x-y)f(x+y)-(x+y)f(x-y)=4xy(x^(2)-y^(2)) The area bounded by the curve C_(1) and C_(2) is

Two curves C_(1)equiv[f(y)]^(2//3)+[f(x)]^(1//3)=0 and C_(2)equiv[f(y)]^(2//3)+[f(x)]^(2//3)=12, satisfying the relation "(x-y)f(x+y)-(x+y)f(x-y)=4xy(x^(2)-y^(2)) The area bounded by the curve C_(2) and |x|+|y|=sqrt(12) is

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = 2a . Here, k is a positive constant.

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = + 2a . Where, k is a positive constant.

A force F=-k/x_2(x!=0) acts on a particle in x-direction. Find the work done by this force in displacing the particle from. x = + a to x = 2a . Here, k is a positive constant.

A force F_(y)=(3x+2)" N" is acting on a body. The work done by this force if it tends to displace the body from x = 0 m to x = 4 m will be