[ 15.Each set X ,contains 5 elements and each set Y ,contains 2 elements and 20UX_(7)=S=U^(n)Y_(r) .If each element of Sbelongs to exactly 10 of the X_(r)^( 's ) and to exactly 4 of Y_(r)^( 's ) ,then find the value of n .]

Each set X_r contains 5 elements and each set Y_r contains 2 elements and uu_(r=1)^(20) X_r =S=uu_(r=1)^n Y_r . If each element of S belongs to exactly 10 of the X'_r s and to exactly 4 of the Y'_r s , then n is :

Suppose A_(1),A_(2),……,A_(20) are twenty sets each having 5 elemennts and B_(1),B_(2),………..,B_(n) are n sets each having 2 elements. Let U_(i=1)^(20)A_(i)=S=U_(f=1)^(n)B_(f) . If each element of S belong to exactly 10 of the A_(i)^(')s and to exactly 4 of the B_(i)^(')s then n is (i) 10 (ii) 20 (iii) 100 (iv) 50

A-set contains 4 elements. It’s power set will contain _______ element.

Let uuu_(i=1)^(50)X_(i)=uuu_(i=1)^(n)Y_(i)=T , where each X_(i) contains 10 elements and each Y_(i) contains 5 elements. If each element of the set T is an element of exactly 20 of sets X'_(i)s and exactly 6 of sets Y'_(i)s , then n is equal to:

Suppose A1,A2,…..A30 are thirty sets each having 5 elements and B1,B2,…….Bn are n sets each having 3 elements.Let each elements of S belongs to exactly 10 of A1,'s and exactly 9 of B1's.Then find the value of n.

Suppose x_1,x_2,….x_(50) are 50 sets each having 10 elements and Y_1,Y_2,….Y_n are n sets each having 5 elements. Let uu_(i=1)^50 X_i=uu_(i=1)^n Y_i=Z and each element of Z belong to exactly 25 of X_i and exactly 6 of Y_i then value of n is

Suppose x_1,x_2,….x_(50) are 50 sets each having 10 elements and Y_1,Y_2,….Y_n are n sets each having 5 elements. Let uu_(i=1)^50 X_i=uu_(i=1)^n Y_i=Z and each element of Z belong to exactly 25 of X_i and exactly 6 of Y_i then value of n is

Suppose A_1 , A_2 ..... A_30 are thirty sets each with five elements and B_1,B_2....B_n are n sets each with three elements such that cap_(i=1)^30 A_i = cap_(j=1)^n B_j = S . If each elements of S belongs to exactly ten of the A_i s and exactly nine of the B_j's then the value of n is