Calculate `lamda_(m)^(0)` of oxalic acid, given that
`lamda_(eq)^(0)Na_(2)C_(2)O_(4)=400Omega^(-1)cm^(2)aq^(-1)`
`lamda_(m)^(0)H_(2)SO_(4)=700Omega^(-1)cm^(2)"mole"^(-1)`
`lamda_(eq)^(0)Na_(2)SO_(4)=450Omega^(-1)cm^(2)eq^(-1)`

If conductivity of water used to make saturated of AgCl is found to be 3.1xx10^(-5)Omega^(-1) cm^(-1) and conductance of the solution of AgCl=4.5xx10^(-5)Omega^(-1)cm^(-1) if lamda_(M)^(0)AgNO_(3)=200Omega^(-1)cm^(2) "mole"^(-1) lamda_(M)^(0)NaNO_(3)=310Omega^(-1)cm^(2) "mole"^(-1) calculate K_(SP) of AgCl

If conductivity of water used to make saturated of AgCl is found to be 3.1xx10^(-5)Omega^(-1) cm^(-1) and conductance of the solution of AgCl=4.5xx10^(-5)Omega^(-1)cm^(-1) if lamda_(M)^(0)AgNO_(3)=200Omega^(-1)cm^(2) "mole"^(-1) lamda_(M)^(0)NaNO_(3)=310Omega^(-1)cm^(2) "mole"^(-1) calculate K_(SP) of AgCl

The conductivity of a saturated solution of a springly soluble salt, MX_(2) is found to be 4.0xx 10^(-6) Omega^(-1) cm^(-1) . If lamda_(m)^(oo) ((1)/(2) M^(2+)) = 50.0Omega^(-1) cm^(2) mol^(-1) and lamda_(m)^(oo) (X^(-)) = 50 Omega^(-1) cm^(2) mol^(-1) , the solubility product of the salt is about

From the following molar conductivities at infinite dilution lamda_(m)^(@) for Ba(OH)_(2)=457.6ohm^(-1)cm^(2)mol^(-1) lamda_(m)^(@) for BaCl_(2)=240.6ohm^(-1)cm^(2)mol^(-1) lamda_(m)^(@) for NH_(4)Cl=129.8ohm^(-1)cm^(2)mol^(-1) Calculate lamda_(m)^(@) for NH_(4)OH

Calculate degree of dissocation of 0.02 M acetic acid at 298K. Given that Lamda_(m) (CH_(3)COOH)= 17.37 S cm^(2) mol^(-1), lamda_(m)^(@) (H^(+)) = 345.8 S cm^(2) mol^(-1), lamda_(m)^(@) (CH_(3)COO^(-)) = 40.2S cm^(2) mol^(-1)