4x^(2)-16x+15

Expression 4x^(2) - 16x + 17 will be minimum when x= ?

If tanalpha is equal to the integral solution of the inequality 4x^2-16 x+15<0 and cosbeta is equal to the slope of the bisector of the first quadrant, then sin(alpha+beta)sin(alpha-beta) is equal to (a) 3/5 (b) 3/5 (c) 2/(sqrt(5)) (d) 4/5

If tanalpha is equal to the integral solution of the inequality 4x^2-16 x+15<0 and cosbeta is equal to the slope of the bisector of the first quadrant, then sin(alpha+beta)sin(alpha-beta) is equal to (a) 3/5 (b) 3/5 (c) 2/(sqrt(5)) (d) 4/5

If tanalpha is equal to the integral solution of the inequality 4x^2-16 x+15<0 and cosbeta is equal to the slope of the bisector of the first quadrant, then sin(alpha+beta)sin(alpha-beta) is equal to (a) 3/5 (b) 3/5 (c) 2/(sqrt(5)) (d) 4/5

If the polynomial p(x)=4x^(4)+4x^(3)-19x^(2)-16x+12 be divided by (x - 2), the remainder is

When x^(5)-5x^(4)+9x^(3)-6x^(2)-16x+13 is divided by x^(2)-3x+a , then quotient and remainders are x^(3)-2x^(2)+x+1 and -15x+11 respectively . Find the value of a .

lim_(x rarr4)((x^(2)-x-12)^(15))/((x^(3)-8x^(2)+16x)^(7))

(4x^(2)-11x+6)/(16x^(2)-9)

The equation whose roots are 0 , 0, 2, 2, -2, -2 is A) x^(6)+8x^(4)-16x^(2)=0 B) x^(6)-4x^(4)-16x^(2)=0 C) x^(6)-8x^(4)+16x^(2)=0 D) x^(6)+4x^(4)+16x^(2)=0