Among noble gases, Xe is quite reactive and form a number of fluorides and oxyfluorides. In these compounds the electrons, from 5p orbitals are excited to 5d orbitals. The predicted shapes of xenon fluorides are linear, square planar and distorted octahedron. The shapes of xeon oxyfluorides can be prodicted by VSEPR theory.
`XeF_(2)` on alkaline hydrolysis yields

The chemical reactivity of noble gases involves the loss of electrons and hence it can form compounds with highly electronegative elements like F and O. Although Xe forms several fluorides, xenone tetrafluoride is the most important among fluorides. The various compounds of xenon involve xenon in first, second or third excited states. The type of hybridisation and shape of XeF_(2) respectively are

The chemical reactivity of noble gases involves the loss of electrons and hence it can form compounds with highly electronegative elements like F and O. Although Xe forms several fluorides, xenone tetrafluoride is the most important among fluorides. The various compounds of xenon involve xenon in first, second or third excited states. The type of hybridisation and number of lone pair (s) of electrons on Xe in XeOF_(2) respectively are

Quantum mechanical calcuations show that mathematical mixing of certain combinaaation of orbitals in a given atom forms hybrid orbitals. The spatial orientations of these new orbitals lead to more stable bonds and are consistent with the observed molecular shapes . The process of orbital mixing is called hybridization and the new atomic orbitals are called hybrid orbitals.- Conditions (i) The no. of hybrid orbitals equal the number of atomic orbitalsmixed. (ii)The type of hybrid orbitals obtained varies with the type of atomic orbitals mixed. Rules to determine hybrid orbitals. Method i:Count no .of atoms directiy attached to central atom + lone pairs+single electrons. Method II: Count sigma - bonds+co-ordinate bonds+ lone pair+single electrons. If the number comes one to be 2 implies sp 5 implies sp^3d/dsp^3 3 implies sp^2 6 implies sp^3d^2/d^2sp^3 4 implies sp^3/dsp^2 7 implies sp^3d^3 Answer the following questions based on above passage : Hybrid states of Xe in XeF_2, XeF_4 and XeF_6 respectively are :

Quantum mechanical calcuations show that mathematical mixing of certain combinaaation of orbitals in a given atom forms hybrid orbitals. The spatial orientations of these new orbitals lead to more stable bonds and are consistent with the observed molecular shapes . The process of orbital mixing is called hybridization and the new atomic orbitals are called hybrid orbitals.- Conditions (i) The no. of hybrid orbitals equal the number of atomic orbitalsmixed. (ii)The type of hybrid orbitals obtained varies with the type of atomic orbitals mixed. Rules to determine hybrid orbitals. Method i:Count no .of atoms directiy attached to central atom + lone pairs+single electrons. Method II: Count sigma - bonds+co-ordinate bonds+ lone pair+single electrons. If the number comes one to be 2 implies sp 5 implies sp^3d/dsp^3 3 implies sp^2 6 implies sp^3d^2/d^2sp^3 4 implies sp^3/dsp^2 7 implies sp^3d^3 Answer the following questions based on above passage : Phosphorous pentachloride in gaseous state exists as a momomer. In solid state, it exists as PCl_5^+. PCl_6^- ions. The hybrid state of P atom in PCl_5 is sp^3d . The hybrid state of P atoms in PCl_4^+ and PCl_6^- will be respectively

The noble gases are chemically inert due to high ionization enthalpy, positive electron gains enthalpy and presence of completely filled orbitals. However, Xe forms a number of compounds such as XePtF_(6) XeF_(2), XeF_(4), XeF_(6) and a number of xenon oxides and oxy fluorides. Xenon fluorides react with fluoride ion acceptors such as PF_(5), AsF_(5), SbF_(3) etc. to form cationic species but with fluoride ion donors such as alkali metal fluorides they forms anionic fluoroanions. They are also hydrolysed by water but their reactivity increases with oxidation state of Xe. The shape and hybridisation of some Xenon oxygen fluorides are given. Select the wrong answer.

The noble gases are chemically inert due to high ionization enthalpy, positive electron gains enthalpy and presence of completely filled orbitals. However, Xe forms a number of compounds such as XePtF_(6) XeF_(2), XeF_(4), XeF_(6) and a number of xenon oxides and oxy fluorides. Xenon fluorides react with fluoride ion acceptors such as PF_(5), AsF_(5), SbF_(3) etc. to form cationic species but with fluoride ion donors such as alkali metal fluorides they forms anionic fluoroanions. They are also hydrolysed by water but their reactivity increases with oxidation state of Xe. The number of lone pairs and bond pairs of electrons around Xe in XeOF_(4) respectively are

The noble gases are chemically inert due to high ionization enthalpy, positive electron gains enthalpy and presence of completely filled orbitals. However, Xe forms a number of compounds such as XePtF_(6) XeF_(2), XeF_(4), XeF_(6) and a number of xenon oxides and oxy fluorides. Xenon fluorides react with fluoride ion acceptors such as PF_(5), AsF_(5), SbF_(3) etc. to form cationic species but with fluoride ion donors such as alkali metal fluorides they forms anionic fluoroanions. They are also hydrolysed by water but their reactivity increases with oxidation state of Xe. Which of the following is not formed by Xe ?

The noble gases are chemically inert due to high ionization enthalpy, positive electron gains enthalpy and presence of completely filled orbitals. However, Xe forms a number of compounds such as XePtF_(6) XeF_(2), XeF_(4), XeF_(6) and a number of xenon oxides and oxy fluorides. Xenon fluorides react with fluoride ion acceptors such as PF_(5), AsF_(5), SbF_(3) etc. to form cationic species but with fluoride ion donors such as alkali metal fluorides they forms anionic fluoroanions. They are also hydrolysed by water but their reactivity increases with oxidation state of Xe. When XeF_(4) is treated with water, it forms ?