[" In a triangle "Delta ABC],[3sin A+4cos B=6" and "],[4sin B+3cos A=1," then the angle "C" is "]

In a triangle ABC,3sin A+4cos B=6 and 4sin B+3cos A=1 hold.Then the angle C equals (measured in degree)

in a Delta ABC,3sin A+4cos B=6 and 3cos A+4sin B=1 then angle C is

In a Delta PQR. if 3sin P+4cos Q=6 and 4sin Q+3cos P=1, then the angle R is equal to:

In Delta ABC, if cos A cos B+ sin A sin B sin C=1 , then the triangle is

In triangle ABC, we are given that 3 sin A +4 cos B=6 and 4 sin B+3 cos A=1 . Then the measure of the angle C is -

In a triangle ABC,sin A-cos B=cos C then angle B is

In a triangle ABC if sin A cos B = 1/4 and 3 tan A = tan B , then the triangle is

In a !ABC if sin A cos B = 1/4 and 3 tan A = B , then the triangle is

In Delta ABC, if cos A cos B+ sin A sin B sin C=1 , then a:b:c =