" 16."tan^(-1)n+cot^(-1)(n+1)=tan^(-1)(n^(2)+n+1)

Show that tan ^(-1) n+cot ^(-1)(n+1)=tan ^(-1)(n^2+n+1)

tan^(-1)(n+1)+tan^(-1)(n-1)=tan^(-1)(8/31)

Show by mathematical induction that tan^(-1) .(1)/(3) + tan^(-1). (1)/(7) + …+tan^(-1). (1)/(n^2 + n +1)= tan^(-1). (n)/(n+2), AA n inN .

tan^(-1)n ,tan^(-1)(n+1) and tan^(-1)(n+2),n in N , are the angles of a triangle if n= 1 (b) 2 (c) 3 (d) None of these

tan^(-1)(m/n)+tan^(-1)((n-m)/(n+m))=?

sum_(n=1)^(n)tan^(-1)((n)/(n))

If x!=n and cot^(-1)x+cot^(-1)(n^(2)-x+1)=cot^(-1)(n-1) then x=

If S= tan^(-1) ((1)/(n^(2) +n+1)) + tan^(-1) ((1)/(n^(2) + 2n+ 3))+ ….+ tan^(-1) ((1)/(1+(n+19) (n+20))) , then tan (s) is equal to

"tan"^(-1)1/3+"tan"^(-1)1/7+……+tan^(-1)(1/(n^(2)+n+1))=