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A particle of mass 1.5 kg moves along x-...

A particle of mass `1.5` kg moves along x-axis in a conservative force field. Its potential energy is given by `V(x)=2x^(3)-9x^(2)+12x,` where all quantities are written in SI units. The plot of this potential energy is given below.
It is seen that the particle can be in stable equilibrium at a point on x-axis, x_(0). When it is displaced slightly from this equilibrium position, It executes SHM with time period T. What is the value of `x_(0)` ?

A

2m

B

3m

C

1m

D

`1.5` m

Text Solution

Verified by Experts

The correct Answer is:
A
`U_(min)at x_(0)=2m`
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