In the cylinder shown in the figure, air is enclosed under the piston. Piston mass M=60 kg, crosssectional area of the cylinder `S_(0)=20 cm^(2)` atmospheric pressure `P_(0)=10^(5) pa alpha=37^(@)`. The air temperature is constant, the friction is negligible.

What is the mass of the goods that must be put on the piston so that the volume of the gas becomes half?

Options

A. 56kg
B. 80kg
C. 110 kg
D. 92 kg

Answer

B

Explanation

P'V'=PV
`RightarrowP'=2P=8xx10^(5)=P_(0)+(mg+Mg)/S_(0)`
`7xx10^(5)xx20xx10^(-4)-600=Mg`
`Rightarrow M=80 kg`