The mass of block is `m_(1)` and that of liquid with the vessel is `m_(2)` The block is suspended by a string (tension T) partically in the liquid. The reading of the weighing machine placed below the vessel

Options

A. can be `(m_(1)+m_(2))g`
B. can be greater than `(m_(1)+m_(2))g`
C. is equal to `(m_(1)g+m_(2)-T)`
D. can be less than `(m_(1)+m_(2))g`

Answer

A, C, D

Explanation

`N=(m_(1)g+m_(2)g)-T`
if`T=0RightarrowN=(m_(1)g+m_(2)g)`
ifT gt0RightarrowN lt `m_(1)g+m_(2)g` and T cannot be negative