How does the total energy stored in the capacitors in the circuit shown in the figure change when first switch `K_(1)` is closed (process-1) and then switch `K_(2)` is also closed (process-2), Assume that all capacitor were initially uncharged?

Options

A. Increases in process-1
B. Increases in process-2
C. Decreases in process-2
D. Magnitude of change in process -2 is less than that in process-1

Answer

A, B, D

Explanation

Equivalent circuit

equivalent capacitance `=(5C)/3`
When `k_(2)` is closed no increasing in energy
when `k_(1)` is closed `E=1/2cqV^(2)=1/2(5C)/3V^(2)=(5CV^(2))/6`